What Is the Factored Form of 8x2 12x?

In mathematics, factorization or factoring is the decomposition of an object (such as a number, a polynomial, or a matrix) into a product of other objects, or factors, which when multiplied together give the original. For example, the number 12 can be factored into 6 × 2, where 6 and 2 are the factors of 12. In this case, the factorization is unique. However, if we allow negative numbers as factors, 12 can also be factored into −4 × −3, or into −2 × −6. So the factors of 12 are −4, −3, −2, 2, 3, and 6. Factoring is usually done in one of two ways: by taking out the greatest common factor, or by using an algebraic method such as the quadratic equation.

The factored form of 8x2 12x is (2x)(4x)(3). The greatest common factor of 8 and 12 is 4, so we take that out first. This leaves us with 2x and 3, which can be factored no further, so the factored form is (2x)(4x)(3).

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-6 is an integer that is often used in mathematical and scientific contexts. It is frequently used as a placeholder value, signifying that no value has been assigned yet. It can also be used to represent a very small or negative number. In some cases, -6 may be used to represent infinity.

-6 is a number that has several uses in mathematics and science. In many cases, it is used as a placeholder value, signifying that no value has been assigned yet. This can be helpful in situations where multiple values are being considered and it is not yet clear which one will be used. It can also be used to represent a very small or negative number. This can be helpful in cases where it is necessary to provide an estimate for a quantity that is not well-known. In some cases, -6 may be used to represent infinity. This can be helpful in situations where it is necessary to consider an infinite quantity, such as in calculus.

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In mathematics, the factored form of a number or expression is the form that it can be written in when it is broken down into factors. The factored form of 8x^2 + 12x - 6 is (8x + 3)(x - 2).

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When factoring an equation, one is looking for numbers that can be multiplied together to equal the coefficients of the given terms. In this case, 8x^2 + 12x - 6, one is looking for two numbers that when multiplied together equal 8, and when added together equal 12. These numbers are 2 and 4. So, the equation can be factored as (2x + 4)(4x - 3).

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There is no definitive answer to this question as it depends on the specific values of 8x^2 + 12x - 6. However, we can narrow it down to a few possibilities. The greatest common factor of 8x^2 + 12x - 6 is either 2, 4, or 6.

The reason that 2, 4, or 6 could be the greatest common factor of 8x^2 + 12x - 6 is because they are all factors of 8x^2 + 12x - 6. In other words, 8x^2 + 12x - 6 is divisible by 2, 4, and 6.

One way to think about the greatest common factor is to imagine that it is the largest number that 8x^2 + 12x - 6 can be divided by evenly. So, if we divide 8x^2 + 12x - 6 by 2, 4, or 6, we will get an integer answer (no remainder).

Dividing 8x^2 + 12x - 6 by 2 gives us 4x^2 + 6x - 3. Since there is no remainder, 2 is a factor of 8x^2 + 12x - 6.

Dividing 8x^2 + 12x - 6 by 4 gives us 2x^2 + 3x - 1.5. Since there is no remainder, 4 is a factor of 8x^2 + 12x - 6.

Dividing 8x^2 + 12x - 6 by 6 gives us 1.3333x^2 + 2x - 1. Since there is no remainder, 6 is a factor of 8x^2 + 12x - 6.

So, the greatest common factor of 8x^2 + 12x - 6 is either 2, 4, or 6. It is impossible to say definitively which one it is without knowing the specific values of 8x^2 + 12x - 6.

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There are a few different ways to approach this question, but ultimately there are three main factors of 8x^2 + 12x - 6: the coefficient of x^2 (8), the coefficient of x (12), and the constant term (-6).

To start, let's consider the coefficient of x^2. This coefficient is 8, which is a factor of 8x^2 + 12x - 6. However, it is also worth noting that 8 is a perfect square (2 * 2 * 2), so we can also consider 8 to be a factor of 8x^2.

The coefficient of x is 12, which is a factor of 8x^2 + 12x - 6. 12 is not a perfect square, but it is a multiple of 4 (3 * 4), so we can also consider 4 to be a factor of 12x.

Finally, the constant term is -6, which is a factor of 8x^2 + 12x - 6. -6 is not a perfect square, but it is a multiple of 3 (-2 * 3), so we can also consider 3 to be a factor of -6.

In summary, the three main factors of 8x^2 + 12x - 6 are the coefficient of x^2 (8), the coefficient of x (12), and the constant term (-6). These three factors can be further broken down into smaller factors, as described above.

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No, 8x^2 + 12x - 6 is not a prime number. There are a few reasons why this is the case. Firstly, the number is not a prime when you factor it. When you factor the number, you get (8x^2 + 12x - 6) = (2x + 3)(4x - 2). As you can see, this is not a prime number. Additionally, the number is not a prime when you take into account the fact that it is divisible by 6. 6 is not a prime number, so 8x^2 + 12x - 6 is not a prime number.

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The difference of 8x^2 + 12x - 6 can be found by subtracting 6 from each side of the equation. This leaves us with 8x^2 + 12x = 0. To solve for x, we can use the quadratic equation. This equation has two solutions, which are -6 and 0.8.

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Since we are looking for the product, we will need to multiply 8x^2 + 12x - 6. We use the distributive property to simplify this equation. 8x^2 + 12x - 6 becomes 8x^2 + 8x + 4x - 6. We can now combine like terms, 8x^2 + 8x + 4x - 6 becomes 16x^2 + 12x - 6. The last step is to multiply each term in the parentheses by -6. 16x^2 + 12x - 6 becomes 16x^2 + 12x - 36. The answer to the equation is 16x^2 + 12x - 36.

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8x^2 + 12x - 6 can be rewritten as (8x^2 + 12x) - 6. This can be further rewritten as 8x(x + 1) - 6. Therefore, the sum of 8x^2 + 12x - 6 is 8x(x + 1) - 6.

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